How many amps (current) are required? Hmmm, not sure.
At the moment, I'm concerned that I've gone for too lower powered transformers. Oh well, they only cost £65 (sob).
I'm not entirely happy with the above statements and would like to address the current required. So, I've had a look at the datasheet for the LM3886
here.
If the chip is supplied +/- 35VDC it will deliver a average output power of 50W when driving a 8 ohm load. I believe W = AV, so A = W/V. Therefore, the transformer must be capable of supplying 50/35 = 1.42A.
However, this isn't the whole story. We need to calculate the peak current required. Thankfully, the datasheet helps.
Peak Current = sqrt( ( 2 x average ouput power ) / load )
So, with a average power output of 50W and a load of 8 ohms....
Peak Current = sqrt ( ( 2 x 50 ) / 8 ) = sqrt ( 12.5 ) = 3.5A
Therefore, the supply needs to be able to deliver: +/- 35VDC @ 3.5A.
My transformers each produce 2 x 25VAC @ 6.4A. However, the rectifying bridge has the effect of increasing the voltage seen on the power rails by a factor of 1.4. So, 25 x 1.4 = +/- 35VDC supplied to the amp.
Assuming I haven't made a silly error and that I roughly understand what I'm talking about (dangerous assumption?) the tranformers I bought should be OK. What I don't understand is why people buy transformers supplying 12A?
As always, grateful for any corrections/comments/clarifications
My useful(?) threads can be found
here.